Since there’s a null byte character guaranteed to be stored at the end of valid characters, then the printf function can be efficiently utilized with the %s format string specifier to output the array’s content. -2. How to pass a string to a function in C is explained in this article. I am setting up a timer to repeat a file every 15 minutes, but i want that file to match the condition that could change within that 15 minute window. if it were not OK to pass char * into such a function, you could not use double str2double( const char* input); passing a string literal as the argument. You need to pass an array of pointers, not a pointer to an array of chars. In C, if you need to amend a string in a called function, pass a pointer to the first char in the string as … C passing char array to a function and pointers - w3programmers.org c c - how passing char* to a function works? - Stack Overflow You need to change the definition of printNames to have the parameter type match what … Passing char arrays to a function - best practice - Arduino Forum Farncombe, Surrey, England. I am lost here, any advice would be appreciated. To do so, simply declare the function parameter as a pointer type. It does so, but only for the local variable. a pointer to char.Also, inside of printNames, you're passing a single char to printf when the %s format specifier expects a char *.Your compiler should have warned you about both of these. GoForSmoke: char duh = “string”; C - Int, char validation functions; C - Buffer manipulation functions; C - Time related functions; C - Dynamic memory allocation; C - Type Casting functions; C - Miscellaneous functions; Get more detail about structure in C programming. The one I don't understand is Method 1. What is the meaning of char *(&Msg1) for the first argument that is passed to the function Foo?